![]() Do you think that such an approach could mean +EV?ġ. What's the probability that a series of 8 blacks (or more) in a row will happen during the next say 221 consecutive spins? You start to chase a series of 8 blacks in a row with a Contre D'Alembert strategy. Now let's assume you watch a roulette wheel and discover that "black 8 times (or more) in a row" did not happen during 953 consecutive spins. This means, with a probability of 50% "black 8 times in a row" will happen once in 221 consecutive spins (on the average!). We said (for the case of the European wheel) that the probability of no black 8 times in a row is (19/37)^8 =~ 0.484% or about 206-to-1. One example for a big roulette gambler's fallacy at an HONEST roulette wheel:
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |